fix(ui): ensure dropdown position stays sticky on interaction

pwa/src/components/common/GameDropdown.tsx

@@ -1,4 +1,4 @@
-import React, { useEffect, useRef } from 'react';
+import React, { useEffect, useRef, useState } from 'react';
 import { createPortal } from 'react-dom';
 import './GameDropdown.css';
 
@@ -38,6 +38,10 @@ export const GameDropdown: React.FC<GameDropdownProps> = ({
 }) => {
     const dropdownRef = useRef<HTMLDivElement>(null);
 
+    // Capture position ONCE on mount (or first render) if not provided
+    // This prevents the menu from jumping if the user clicks inside it (changing lastClickPos)
+    const [capturedPos] = useState(() => position || lastClickPos);
+
     // Handle click outside
     useEffect(() => {
         if (!isOpen) return;
@@ -52,7 +56,6 @@ export const GameDropdown: React.FC<GameDropdownProps> = ({
         document.addEventListener('mousedown', handleClickOutside);
 
         // Handle scroll to update position or close? 
-        // For now, simpler to just close on scroll or let it float (fixed pos)
         const handleScroll = () => {
             // Optional: onClose(); 
         };
@@ -66,9 +69,10 @@ export const GameDropdown: React.FC<GameDropdownProps> = ({
 
     if (!isOpen) return null;
 
-    // Use passed position or fallback to last click position
+    // Use passed position (if updated dynamically) or fall back to the captured sticky position
-    const targetX = position ? position.x : lastClickPos.x;
+    const target = position || capturedPos;
-    const targetY = position ? position.y : lastClickPos.y;
+    const targetX = target.x;
+    const targetY = target.y;
 
     let x = targetX - 10;